孔子，生日快乐！

Posted by Joachim September 28, 2010 in the Group General Discussion .

Today would be the 2561st birthday of Kongzi.

What a number to celebrate?

[2561 is the hypotenuse of 2 primitive Pythagorean triples: 2561^2 = 639^2+2480^2 = 1311^2+2200^2]

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