孔子，生日快乐！

Joachim

September 28, 2010, 10:16 AM posted in General Discussion

Today would be the 2561st birthday of Kongzi.

What a number to celebrate?

[2561 is the hypotenuse of 2 primitive Pythagorean triples: 2561^2 = 639^2+2480^2 = 1311^2+2200^2]

More here http://people.chinese.cn/kongfuzi/article/.